SOLUTION: Solve log a (8x+5)=log a (4x+29). Thank you for any help you can provide.
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Question 44101
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Solve log a (8x+5)=log a (4x+29). Thank you for any help you can provide.
Answer by
fractalier(2101)
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Well if logarithmic expressions are equal, their arguments are too, so that if
log_a (8x+5) = log_a (4x+29)
then
8x + 5 = 4x + 29
4x = 24
x = 6