SOLUTION: Solve log a (8x+5)=log a (4x+29). Thank you for any help you can provide.
Algebra.Com
Question 44101: Solve log a (8x+5)=log a (4x+29). Thank you for any help you can provide.
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Well if logarithmic expressions are equal, their arguments are too, so that if
log_a (8x+5) = log_a (4x+29)
then
8x + 5 = 4x + 29
4x = 24
x = 6
RELATED QUESTIONS
Can anyone help me solve this log problem:
Solve log(lower a) (8x+5)=log(lower... (answered by stanbon)
Solve log a(8x+5)=log a(4x+29)
The "a" is subscript in this... (answered by scott8148)
solve log a (8x+5)=log a (4x+29) My answer is 6, is that right. thanks for... (answered by venugopalramana)
Solve log subscript a(8x+5)=log subscript a(4x+29).... (answered by Nate)
I also need help with
"log^a(8x+5)=log^a(4x+29)"... (answered by funmath)
Solve for x
5+ log x = log x^6
any help you can give would be greatly... (answered by Positive_EV)
If f(x)=x^2+5, find f(a+h)-f(a). Thank you for any help you can... (answered by stanbon)
Given that log a (x)=3.58 and log a (y)=4.79, find log a (y/x). Thank you for any... (answered by fractalier)
solve LOGa(8x+5) =LOGa(4x+29)
the a is lower than the word LOG. What does this mean?
(answered by ankor@dixie-net.com)