SOLUTION: Solve for m. Round your answer to 4 decimal places if necessary. log5 m=1/3 log5 125 a.m = 2.6265 b.m = 5 c.m = 15 d.m = 41.6667

Algebra.Com
Question 440221: Solve for m. Round your answer to 4 decimal places if necessary.
log5 m=1/3 log5 125
a.m = 2.6265
b.m = 5
c.m = 15
d.m = 41.6667

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
log5 m=1/3 log5 125



5^0 = m/125^(1/3)=
1 =
= m
5 = m




RELATED QUESTIONS

Solve -14 > 5(2m - 3) - m. a) {m | m < 1} b) {m | m < 1/9} c) {m | m > 1} d) (answered by jim_thompson5910,stanbon)
Log5^(m-9)=3 (answered by lwsshak3)
I need help with this one (m^4)^3(m^2)^9 over, (m^3)^2 A) m^5 B) m^3... (answered by edjones)
simplfy {{{(m^2)/(m^2-m)-(3m-2)/(m^2-m)}}}= A){{{(m+2)/(m)}}} B){{{(m-2)/(m)}}}... (answered by josmiceli)
a. m = 1/3, m = 3/9 - Parallel b. m = -5/3 , m = -2 - Neither parallel nor... (answered by Fombitz,Alan3354)
If m is an integer, for what value of m is 3^m <100< 3^m+1 ? a) 1 b) 2 c) 3 d)... (answered by Fombitz)
. Given the figure shown with AX || DY , find the following: ____(a) m(<1)... (answered by solver91311)
If m is an odd integer, what is the second consecutive even integer preceding m? a) m-4 (answered by richwmiller)
Calculate the standard error. May normality be assumed? (Round your answers to 4 decimal... (answered by textot)