SOLUTION: hello. i need help with these few problems. {{{ log ( 2, 25 ) }}} and {{{ log ( 2, 3/5 ) }}} and {{{ log ( 2, 15 ) }}} and {{{ log ( 2, 75 ) }}} i just dont know how to approach th
Algebra.Com
Question 439520: hello. i need help with these few problems. and and and i just dont know how to approach these. Thanks
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log ( 2, 25 ) }}} and and and
-------------
There is a Law of Logs called the change of base law.
It says: loga(b) = logc(b)/logc(a)
where c is any base you care to use.
-----------------------------------------
Your problem:
log2(25) = log(25)/log(2) = 1.3979/0.3010 = 4.644
================
Using your calculator:
log2(3/5) = log(3/5)/log(2) = -0.7370
---
log2(75) = log(75)/log(2) = 6.2288
=======================================
Cheers,
Stan H.
RELATED QUESTIONS
I need help solving these problems.
{{{ 2log(3,x)-log(3,x-4)=(2)+log(3,2)}}}
and
(answered by josmiceli,lwsshak3)
How do i write these as a single logarithm?
1) (log 3 - log 4) - log 2
2) log 2 +... (answered by Boreal)
How to find value log log(40) when I am given the values of log(2) and log(5) in the... (answered by fractalier)
How do I solve these problems?
1. log(2 - x) = 0.5
2. log(x + 25) = log(x + 10) + (answered by Theo)
log(x)=log(3)+log(x-6)
log(X)+log(x-5)=log(6)
I really need help with this 2... (answered by stanbon)
2 log 3 + log 5 - log... (answered by edjones,Alan3354)
The teacher gave us problems based on the properties of logarithms. I understand some but (answered by stanbon)
I dont know how to do this problem because of the square root, I couldnt even write it... (answered by Edwin McCravy)
I don't even know where to start with this one, looking for help
Solve for x
27.)... (answered by ankor@dixie-net.com)