Hi

1/2[log(x+2)+log(x+3)]=1

  log(x+2)*(x+3) = 2

 10^2 = (x+2)*(x+3)

  x^2 + 5x - 94 = 0

 x = 7.5125  |tossing out negative solution as being Extraneous 

 

Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
 1/2[log(x+2)+log(x+3)]=1

[log(x+2)+log(x+3)]=2

log(x+2)(x+3)=2

(x+2)(x+3)=10^2

x^2+5x+6 = 100

x^2+5x-94 = 0

applying the quadratic formula gives you your answers:

x = {-12.512, 7.512}

then negative solution is extraneous, toss it out leaving:

x = 7.512







 

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