# SOLUTION: log[4]x + log[4](x+1)=log[4]6 Solve the logarithmic equation. (To ensure my problem makes sense, the 4's are supposed to be "subscrip

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: log[4]x + log[4](x+1)=log[4]6 Solve the logarithmic equation. (To ensure my problem makes sense, the 4's are supposed to be "subscrip      Log On

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 Click here to see ALL problems on logarithm Question 431446: log[4]x + log[4](x+1)=log[4]6 Solve the logarithmic equation. (To ensure my problem makes sense, the 4's are supposed to be "subscripts" of the log, I just didn't know how to type it other than this. Thank you for your help! Please respond as quickly as possible.Answer by nerdybill(7003)   (Show Source): You can put this solution on YOUR website!apply log rules: log[4]x + log[4](x+1)=log[4]6 log[4](x(x+1))=log[4]6 x(x+1)=6 x^2+x = 6 x^2+x-6 =0 factoring the left: (x+3)(x-2) = 0 x = {-3, 2} we can throw out the -3 (extraneous solution) leaving: x = 2