SOLUTION: log[4]x + log[4](x+1)=log[4]6
Solve the logarithmic equation.
(To ensure my problem makes sense, the 4's are supposed to be "subscrip
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Question 431446: log[4]x + log[4](x+1)=log[4]6
Solve the logarithmic equation.
(To ensure my problem makes sense, the 4's are supposed to be "subscripts" of the log, I just didn't know how to type it other than this. Thank you for your help! Please respond as quickly as possible.
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
apply log rules:
log[4]x + log[4](x+1)=log[4]6
log[4](x(x+1))=log[4]6
x(x+1)=6
x^2+x = 6
x^2+x-6 =0
factoring the left:
(x+3)(x-2) = 0
x = {-3, 2}
we can throw out the -3 (extraneous solution) leaving:
x = 2
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