SOLUTION: Hey hows it goin I ran into a little issue with log's I was wondering if you could help me solve this one. The base of the log's are a understood 10. log4x=log5+log(x-4)

Question 423152: Hey hows it goin I ran into a little issue with log's I was wondering if you could help me solve this one. The base of the log's are a understood 10.
log4x=log5+log(x-4)
Found 2 solutions by jim_thompson5910, josmiceli:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
log4x=log5+log(x-4)

log4x=log[5(x-4)]

4x=5(x-4)

4x=5x-20

4x-5x=-20

-x=-20

x=20

If you need more help, email me at jim_thompson5910@hotmail.com

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Jim

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

The logs are equal, so

check answer:

OK

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