You can
put this solution on YOUR website!first change the base, so that all are base 3...i will not write the base anymore, to ease the readability:
Since log3 to base 3 is 1, we get
135 = 5*27
405 = 5*81
and 15 = 5*3, so we get:
(log27+log5)(log3+log5) - log5(log81+log5)
log27log3 + log27log5 + log3log5 + (log5)^2 - log81log5 - (log5)^2
Now, log27 to base 3 is 3
and log81 to base 3 is 4, so...
3log3 + 3log5 + log5 + (log5)^2 - 4log5 - (log5)^2
everything cancels except for the 3, so this is the answer!
jon
