SOLUTION: {{{ log( 3/2, 3 ) }}}
Algebra.Com
Question 409740:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log( 3/2, 3 )
====
= [log(3/2)]/[log(3)]
---
= [log(3)-log(2)]/log(3)
----
= 1-log3(2)
================
I'm not sure how far you want to go with the rest of this.
===============
Cheers,
Stan H.
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