SOLUTION: log4(x^2)-log4(4x-4)=0 I could really use some help solving this one.

Algebra.Com
Question 409370: log4(x^2)-log4(4x-4)=0
I could really use some help solving this one.

Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
log4(x^2)-log4(4x-4)=0
..
log4(x^2)-log4(4x-4)=0
log4(x^2)/(4x-4)=0
convert to exponential form,
(x^2)/(4x-4)=4^0=1
x^2=4x-4=0
x^2-4x+4=0
(x-2)^2=0
x=2 (multiplicity 2)

RELATED QUESTIONS

I am working on solving this inequality and could really use some help. (x-3)/(x+4)>2... (answered by smartdude17)
I need help solving... (answered by Alan3354)
(log4(log4^x))=-4 (answered by jsmallt9)
I hope someone can clarify this. I'M CONFUSED!!! 2(log4 x + logx 4)=5 My working:... (answered by Alan3354)
I need help in solving this equation: 2log x - log4 = 1/2... (answered by scott8148)
How do I simplify this and find x? log4(x-4) + log4(x+2) =... (answered by vasumathi)
Log4(x+2)+Log4(x-4)=2 (answered by josgarithmetic)
log4 x-log4 (x+3)+log4... (answered by ewatrrr)
log4 x- log4 (x+3) + log4 (X^2... (answered by ewatrrr)