SOLUTION: solve for x. log(2)^x=8+9log(x)^2

Question 408507: solve for x. log(2)^x=8+9log(x)^2
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
It is very difficult to understand what your equation is. Is it

or something else?

Tutors are more likely to help when the problem is clearly stated. Logarithmic expressions can be particularly difficult. With logarithms I suggest you learn how to read them and then post them in part English and part Math terms. For example,

is the "base 3 log of (x+y)". Note the use of parentheses. The "base 3 log of x + y" would be:

which is not the same thing.

BTW, if your equation was

(or something close to it), then there are no exponents in this equation!. This equation is "the base 2 log of x = 8 + 9 times the base x log of 2".
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