SOLUTION: if x^2 + y^2 = 6xy prove that: 2log(x+y) = log x + log y +3log 2 plz i want the answer quickly

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Question 407766: if

x^2 + y^2 = 6xy
prove that:
2log(x+y) = log x + log y +3log 2


plz i want the answer quickly
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Hmm. Since you abbreviated please with the letter "z", I'll solve the problem for you, for your "enlightenment", hahaha.
x%5E2+%2B+y%5E2+=+6xy+ <==> x%5E2+%2B+2xy+%2B+y%5E2+=+8xy
==> %28x%2By%29%5E2+=+8xy
Take logs of both sides:
2log%28%28x%2By%29%29+=+log8++%2Blog+x++%2B+logy,
after applying additive property of logs.
Hence it follows that
2log%28%28x%2By%29%29+=+3log2+%2B+logx+%2Blogy.