SOLUTION: solve algebraically e^x = -x

Question 404418: solve algebraically e^x = -x
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
It's quite clear that no can satisfy the equation. (, but ). Considering the graphs of both and -x, there is only one solution (or intersection point), and it lies between -1 and -1/2.
(This is because and .
Now for small values of x.
So to get an approximate value for the root, solve

==> , or
.
==>

. Eliminating the bottom value the answer is

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