SOLUTION: I would appreciate help with the following logarithmic equation. I need to solve out to two decimal places. log(x+3)+log(x-2)= log14

Question 394323: I would appreciate help with the following logarithmic equation. I need to solve out to two decimal places.
log(x+3)+log(x-2)= log14
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
log(x+3)+log(x-2)= log14
use logarithm rule for multiplication
log(x+3)(x-2) =log14
(x+3)(x-2)=14
x^2+x-6=14
x^2+x-20=0
solve by factoring
(x+5)(x-4)=0
ans: x=-5(reject,logarithm>0)
x=4
check:
log(x+3)+log(x-2)= log14
log7+log2=log14
.8451+.3010=1.146
1.146=1.146
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