SOLUTION: log(5/2x) its in logarithm form i know how to get the answer for x i just dont how to get this equation from a log to exponential form
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Question 393612: log(5/2x) its in logarithm form i know how to get the answer for x i just dont how to get this equation from a log to exponential form
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
log(5/2x) its in logarithm form i know how to get the answer for x i just dont how to get this equation from a log to exponential form
assuming log(5/2)x is what is meant,
this expresses the logarithm of a number, in this case, (5/2)x
This is usually written in the form, y = log x, which says the logarithm of x is equal to y
According to the definition of logarithms, the base, in this case is 10, raised to the logarithm of the number is equal to the number. So in this example the exponential form is base^logarithm = number,ie;10^y=x
Now, back to your problem, the base =10, the number=(5/2)x,and the logarithm of the number, which is not given so we will call it y. So in exponential form it should look like this:
10^y=(5/2)x
given y, you can then solve for x
Hope this helps!
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