Hi

Solve for x 

log x +log(x-5)=log14

log x(x-5)/14 = 0

 10^0 = x(x-5)/14

  1 = x(x-5)/14

  14 = x(x-5)

 x^2 - 5x - 14 = 0

factoring

 (x+2)(x-7)=0 Note:SUM of the inner product(2x) and the outer product(-7x) = -5x

 (x+2)= 0  negative solution is extraneous 

 (x-7)=0 

    x = 7 

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