SOLUTION: How do you solve 2log[base 6](x)-2log[base 6] (x-4)= 1
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Question 393174: How do you solve 2log[base 6](x)-2log[base 6] (x-4)= 1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve 2log[base 6](x)-2log[base 6] (x-4)= 1
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Divide thru by 2 to get:
log6(x)-log6(x-4) = 1/2
---
log6[x(x-4)] = 1/2
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x(x-4) = 6^(1/2)
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x^2-4x-6^(1/2) = 0
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Use the Quadratic formula to find a positive solution
because x must be positive in the original problem statement:
x = [4 + sqrt(16-4*6^(1/2))]/2
---
x = [4 + sqrt(6.202)]/2
---
x = 3.245..
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That is not an acceptable answer because 3.234-4 is negative
and you cannot take a log of a negative number.
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Conclusion: No solution
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Cheers,
Stan H.
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