SOLUTION: Can you help me solve this? I have a really hard time with Logarithms: log(2x+7) base 4 = log(81) base 3
Algebra.Com
Question 391133: Can you help me solve this? I have a really hard time with Logarithms: log(2x+7) base 4 = log(81) base 3
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
log(2x+7) base 4 = log(81) base 3
<==> log(2x+7) base 4 = 4
<==>
==> 2x + 7 = 256,
x = 249/2.
RELATED QUESTIONS
Solve and check
a)2logm + 3logm = 10
b)log(base 3)x^2 - log(base 3)2x = 2
c)log(base... (answered by solver91311)
i really don't know where to begin with this problem at all?
given log base a 2= 0.431... (answered by bucky)
1. Solve the following equations
a) log(base 5)x+2 + log(base 5) x-2 - log(base 5)4 =... (answered by mananth)
1.Write as a difference of logarithms
a) log(base 4)11
b) log(base 3)12
c) log(base... (answered by MathLover1)
Please help me with this logarithm
log(base 4)n = log(base 4)81+(1/2)log(base... (answered by Alan3354)
can you help me solving this equation: solve for x
log base 2 (2x)= 4- log base 2... (answered by Cromlix)
Solve for x:
(A.) (5/2) log(base 4)4 = log(base 4)(2x-3)
(B.) Log(base 3)(x+2)-... (answered by stanbon)
I have been having a really hard problem with these logs
1. Log base 8 X=1/3
2. Log (answered by alicealc,nerdybill)
Solve and check
a) 1og(base 7)(x+4) + log(base 7)(x-2) = 1
b) log(base 2)(2m+4) -... (answered by MathLover1)