# SOLUTION: Use the exponential decay model A=Pe^(kt) to solve the following proublem. The half-life of plutonium-238 is days. The initial amount is 100 grams. a)find the value of K to four

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Use the exponential decay model A=Pe^(kt) to solve the following proublem. The half-life of plutonium-238 is days. The initial amount is 100 grams. a)find the value of K to four       Log On

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 Question 387320: Use the exponential decay model A=Pe^(kt) to solve the following proublem. The half-life of plutonium-238 is days. The initial amount is 100 grams. a)find the value of K to four places. b) write the formula for the amount of plutonium-238 present at the end of T days. c)How much of the initial amount will remain after 30 days? Round the answer to the nearest tenth gram. I know this seems like alot but I swear it's all one proublem just has Three parts to it, been having trouble, thank you sooo much in advance!!! :)Answer by stanbon(57246)   (Show Source): You can put this solution on YOUR website!Use the exponential decay model A=Pe^(kt) to solve the following proublem. The half-life of plutonium-238 is days. The initial amount is 100 grams. a)find the value of K to four places. (1/2)P = P*e^(k*238) e^(238k) = 1/2 Take the natural log of both sides to get: 238k = ln(1/2) k = -0.002912 --------------------------- b) write the formula for the amount of plutonium-238 present at the end of T days. A(t) = P*e^(-0.002912t) --------------------------- c)How much of the initial amount will remain after 30 days? Round the answer to the nearest tenth gram. A(30) = 100*e^(-0.002912*30 --- A(30) = 100*0.916337 A(30) = 91.6337 grams ========================== Cheers, Stan H. =============