SOLUTION: log3x+log9=0
Algebra.Com
Question 385683: log3x+log9=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log3x+log9=0
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log[9*3x] = 0
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27x = 10^0
---
27x = 1
x = 1/27
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Cheers,
Stan H.
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