SOLUTION: solve for x: log x + (log x + 21)=2

Question 382936: solve for x: log x + (log x + 21)=2
Found 2 solutions by Earlsdon, CharlesG2:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for x:
Apply the product rule:
Simplify the argument.
Rewrite this in exponential form.
Rewrite as a quadratic equation in standard form.
Factor.
Apply the zero product rule.
or so...
or Discard the negative solution as the log of a negative number is not real.

Check:
=
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
solve for x: log x + (log x + 21)=2

log x + (log x + 21) = 2
thinking you meant log x + 21 and not log (x + 21), sorry if this was not the case
2log x + 21 = 2
2log x = -19
log x = -19/2 = -9.5
logarithmic rule: if logb x = y, then b^y = x
assuming base is 10
10^(-9.5) = x
3.162278 * 10^(-10) rounded places after the decimal point to 6 places

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