SOLUTION: log(base4)x-2log3=1
How can I solve Logarithms with different bases? How can I change the bases and make it similar.
Algebra.Com
Question 382902: log(base4)x-2log3=1
How can I solve Logarithms with different bases? How can I change the bases and make it similar.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log(base4)x-2log3=1
--------
log4(x) - log10(9) = 1
----
log(x)/log(4) - log(9)/log(10) = 1
-----
log(x)/log(4) - log(9) = 1
-----
Multiply thru by log(4) to get:
-----------
log(x) - log(9)*log(4) = log(4)
----------
log(x) = log(9)*log(4) + log(4)
---
log(x) = 1.176571...
x = 10^1.176571
x = 15.016587)
==================
Cheers,
Stan H.
==================
RELATED QUESTIONS
I don't understand how to solve this problem. How can you solve an equation with... (answered by scott8148)
Please how can you solve logariths with different bases
(answered by harpazo)
if r=log*base4* x and s=log*base4* y
how can i write log*base4*(64x^(6)y^(3))^(2) using... (answered by jsmallt9)
Hi. I need some help with a math problem.
log[x] (x+4) + log[3] (x-2) = 3
I have no... (answered by richard1234)
How do I solve:
Log x + log (13 -3x) = 1
(Bases are... (answered by scott8148)
Hello. I am trying to solve this exponential function but am not successful. Can you help (answered by ikleyn)
log[base2](x+1)-log[base4]x=1
note: book says to change log[base4]x to base 2.
ANSWER (answered by greenestamps)
Solve for x:
a) log base4 (x+2) + log base4 (n-4)=2
b) log base2 (x^2-2) - log base2... (answered by stanbon)
Use properties of logarithms to solve the equation log(base4)(x+2)=... (answered by ewatrrr)