SOLUTION: Please show how to do it.
Solve the equation.
log base 2 (2x+8) - log base 2 (2x^2+21x+61) = -3
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Question 380172: Please show how to do it.
Solve the equation.
log base 2 (2x+8) - log base 2 (2x^2+21x+61) = -3
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ -\ \log_2\left(2x^2\ +\ 21x\ +\ 61\right)\ =\ -3)
First use "The difference of the logs is the log of the quotient"
 - \log_b(y) = \log_b\left(\frac{x}{y}\right))
\ =\ -3)
Then use the definition of the logarithm function:
 \ \ \Rightarrow\ \ b^y = x)
So:
\ =\ 2x^2\ +\ 21x\ +\ 61)
Then just solve the factorable quadratic.
John
My calculator said it, I believe it, that settles it
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