SOLUTION: log[64](32)=0 I keep coming up with no solution, but that isn't one of the answers on my pretest. Thanks!

Question 378530: log[64](32)=0
I keep coming up with no solution, but that isn't one of the answers on my pretest. Thanks!
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
Where's the variable?? Without a variable there is no "solution" to be found. The equation is either true or not.

As for whether

is true or not, just rewrite it in exponential form:

Since any non-zero number to the zero power is 1 this simplifies to:

This is clearly a false statement.

P.S. We can find what equals without using calculators. Since both 64 and 32 are powers of 2 ( and , will simplify easily if we use the base conversion formula, , to convert this base 64 logarithm into a base 2 logarithm:

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