Hi

log 2 (x-1) - log 2 (x+3) = log 2 (1/x)

log 2 (x-1) - log 2 (x+3) - log 2 (1/x)=0



=0



2^0 = (x-1)/(x+3)(1/x)



1 = x(x-1)/(x+3)

(x+3) = x^2 -x

x^2 -2x - 3 = 0

(x-3)(x+1)= 0

(x-3)=0    x = 3

(x+1)= 0   x = -1 reject as a solution

Any solution that makes an argument (or base) zero or negative must be rejected.

log 2 ((-1)-1) - log 2 ((-1)+3) = log 2 (1/(-1))

 

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