SOLUTION: logx -log7-log8
written as a single logarithm
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Question 376611: logx -log7-log8
written as a single logarithm
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
-\log(7)-\log(8))
... Start with the given expression.
-(\log(7)+\log(8)))
... Factor out a negative from the last two terms.
-\log(7\times8))
... Combine the last two logs using the identity
-\log(56))
... Multiply
)
... Combine the two logs using the identity
So -\log(7)-\log(8)=\log(\frac{x}{56}))
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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