SOLUTION: how to solve: log2x-log(x-7)=log3

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Question 375866: how to solve:
log2x-log(x-7)=log3


Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi


log2x-log(x-7)=log3
log2x-log(x-7)-log3=0
log(2x/3(x-7) = 0

10 ^0 = 2x/3(x-7)
1 = 2x/3(x-7)
3(x-7)= 2x
3x - 21 = 2x
x = 21
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