SOLUTION: Can i Have a answere for the following two questions, thanks very much 1) 0.04^log(base 0.2)3 2) 10^1+ln5

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Can i Have a answere for the following two questions, thanks very much 1) 0.04^log(base 0.2)3 2) 10^1+ln5      Log On


   

Question 37537: Can i Have a answere for the following two questions, thanks very much

1) 0.04^log(base 0.2)3
2) 10^1+ln5
Answer by AnlytcPhil(1810) About Me  (Show Source):
You can put this solution on YOUR website!
1) 0.04^log(base 0.2)3 
2) 10^1+ln5


0.04log0.23 

0.04 can be written in terms of the base 0.2, that is,

0.04 = (0.2)˛

So substitute (0.2)˛ for 0.04

[(0.2)˛]log0.23

Remove the brackets by multiplying the exponents 2 and log0.23

(0.2)2·log0.23

Use this rule of logarithms in the exponent:   A·logBC = logBCA

(0.2)log0.23˛  

Substitute 9 for 3˛

(0.2)log0.29

Use this rule of logarithms:  BlogBA = A

Answer: 9


2) 101+ln5



You can't simplify that, so I'd just punch it into a calculator
and give the decimal value

                406.8533651

Edwin
AnlytcPhil@aol.com