SOLUTION: 3^-2 = (1/9)
I need to rewrite as a logarithm equation
Thanks
Algebra.Com
Question 375319: 3^-2 = (1/9)
I need to rewrite as a logarithm equation
Thanks
Answer by Jk22(389) (Show Source): You can put this solution on YOUR website!
log(3^-2) = log(1/9)
-2*log(3) = -log(9),
with the properties log(ab)=log(a)+log(b), log(1)=0, log(a^b)=b*log(a)
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