SOLUTION: log4^8

Algebra.Com
Question 37530: log4^8
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
log4^8 = log 4*4*4*4*4*4*4*4
log 4*4*4*4*4*4*4*4 =
log4 + log4 + log4 + log4 + log4 + log4 + log4 + log4 =
8log4

RELATED QUESTIONS

log4^2 + log4^8 =... (answered by ankor@dixie-net.com)
Solve for x: log4^8 + log4^6 =... (answered by Nate)
Solve log4 (m+2)-log4 (m-5)=log4... (answered by ikleyn,josmiceli)
Simplify: ½ log4 8 + log4 32 - log4... (answered by ikleyn)
log4 (2x+5) =... (answered by MathLover1)
2logx+8=log4 (answered by Theo)
log4(13x+12) - log4(x-8) = 2 Solve for... (answered by Fombitz)
prove that : {{{25^(log8)*8^(log4)}}}{{{""=""}}}{{{64}}} (answered by Edwin McCravy)
9-log4(x+8)=8 I keep getting stuck at log4(x+8)= -1 (answered by stanbon,Alan3354)