SOLUTION: solve logarithmic equation
log(3+x)-log(x-4)=log2
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Question 374619: solve logarithmic equation
log(3+x)-log(x-4)=log2
Answer by rfadrogane(214) (Show Source): You can put this solution on YOUR website!
solve logarithmic equation
log(3+x)-log(x-4)=log2
Sol'n:
from log a - log b = log (a/b)
then,
log [(3+x)/(x-4)]= log 2, then take the antilog on both side,
3+x/x-4 = 2
3+x = 2(x-4)
3+x = 2x-8
x = 11 ---answer
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