SOLUTION: log(7-2x)=log(x+5)
Algebra.Com
Question 37381: log(7-2x)=log(x+5)
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Since log(7 - 2x) = log(x + 5), we can exponentiate both sides, thus putting the arguments equal...thus we have
7 - 2x = x + 5 and
3x = 2 and
x = 2/3
Check to be sure this is a legal solution...it is, so
x = 2/3
RELATED QUESTIONS
2 ^ log(2,(2x + 3)) + 5^log(5,(x + 7)) = 7 ^ log_7(2x +... (answered by MathLover1,Alan3354)
log x^5 - Log x^3 = log 6x - log... (answered by Fombitz)
log(x+9)=log(2x-7) (answered by nerdybill)
log 10x - log (2x - 3) = log 7 solve for... (answered by stanbon)
log (2x+5)+log... (answered by Fombitz,solver91311)
log (2x + 2) – log (x + 5)... (answered by nerdybill)
log x-log 10=14
log (x+9)= log (2x-7)
log x^2+ log... (answered by jsmallt9)
Solve for x:
(A.) Log(base 5)7 + log(base 5)8 = log(base 5)(2x-4)
(B.) Log(base 3)... (answered by Nate)
log(2x + 3)=log... (answered by nerdybill)