SOLUTION: how do i solve log base 3 (x-8)+ log base 3 x =2

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Question 372076: how do i solve log base 3 (x-8)+ log base 3 x =2
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
log base3 (x-8)+ log base 3 x = 2

= 2

3^2 = (x-8)x
solving for x
9 = x^2 - 8x
0 = x^2 - 8x - 9
factoring
(x-9)(x+1) = 0
(x-9)= 0 x = 9
(x+1)= 0 x = -1 Cannot use
x = 9
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