SOLUTION: Solve:
log base 4 (X) + Log base 8 (x) = 1
ln X/ln 4 + ln X/ln 8=1
2 ln X/2 ln 4 + ln X/ln 8 = 2
ln X^2 + ln X = 2 ln 8
ln X^2 + ln X - 2 ln 8 = 0
ln X^2(x)-2 ln 8 = 0
ln X
Algebra.Com
Question 372029: Solve:
log base 4 (X) + Log base 8 (x) = 1
ln X/ln 4 + ln X/ln 8=1
2 ln X/2 ln 4 + ln X/ln 8 = 2
ln X^2 + ln X = 2 ln 8
ln X^2 + ln X - 2 ln 8 = 0
ln X^2(x)-2 ln 8 = 0
ln X^3 - 2 ln 8 = 0
ln X^3 / 2 ln 8 = 0
ln X^3/ln 64
I am not sure this is done right?????
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
By definition,
.
.
.
.
They both equal so set them equal to each other.
Substituting,
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