SOLUTION: solve for x :
log8+3logx=log2x
Algebra.Com
Question 368024: solve for x :
log8+3logx=log2x
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
I'm assuming everything is log base 10...
log8+3logx=log2x
log8+logx^3=log2x
log(8x^3)=log2x
8x^3 = 2x
8x^2 = 2
x^2 = 2/8
x^2 = 1/4
x = 1/2
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