SOLUTION: solve the equation: log4 + 2logx =log (x+3)^2

Question 368020: solve the equation:
log4 + 2logx =log (x+3)^2
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
log4 + 2logx =log (x+3)^2
log4 + logx^2 =log (x+3)^2
log(4x^2) =log (x+3)^2
4x^2 =(x+3)^2
2x =x+3
x = 3
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