SOLUTION: log4(x-1)+log2(3x+4)
is it a trick because it is not equal to anything?
also we cannot use calculators
thanks,GodBless
Algebra.Com
Question 367587: log4(x-1)+log2(3x+4)
is it a trick because it is not equal to anything?
also we cannot use calculators
thanks,GodBless
Answer by Jk22(389) (Show Source): You can put this solution on YOUR website!
log4(x-1)+log2(3x+4) = log4(x-1)+log(3x+4)/log(2)
= log4(x-1)+log4(3x+4)*log(4)/log(2)
= log4(x-1)+2log4(3x+4)
= log4((x-1)(3x+4)^2)
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