SOLUTION: I need to solve the following equation rounded to 3 decimal places: I need to see how it's done, so i can practice ln x + ln (x+7) = -5 Thank you.

Question 366154: I need to solve the following equation rounded to 3 decimal places:
I need to see how it's done, so i can practice
ln x + ln (x+7) = -5
Thank you.
Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
ln x + ln (x+7) = -5
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Since ln(A) + ln(B) = ln(AB)
you get:
ln[x(x+7)] = -5
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That means "the exponent of "e" that gives you
x^2+7x is -5"
------------------
Solve x^2+7x = e^-5
---
x^2 + 7x = 0.0067
x^2 + 7x - 0.0067 = 0
----
Positive solution:
I graphed the equation and found zeroes at
x = 9.57x10^-4
===================
Cheers,
Stan H.
===================
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