SOLUTION: my question is: assume that x and y are positive numbers. Use the properties of logarithms to write the expression below in terms of the logarithms of x and y: ln(x(y^7))

Question 363595: my question is:
assume that x and y are positive numbers. Use the properties of logarithms to write the expression below in terms of the logarithms of x and y:
ln(x(y^7))

it is square root of y with a number 7 in the beginning dip of the square root.
I have tried:
lnx+lny^1/7
1/7(lnx+lny)
one other question:
Assume that x and y are positive numbers. Use the properties of logarithms to write the expression below as the logarithm of one quantity. 2 ln(x) +
1/2 ln(y)(and it is "ln" and not '#1" by the n's.

Ive tried lnx^2square root y

Found 2 solutions by edjones, ewatrrr:
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
ln(x(y^7))
=ln(x)+ln(y)*7
.
Ed
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi,
ln(x(y^7))
writing the expression in terms of the logarithms of x and y:

ln(x(y^7)) = lnx + lny^7
2 ln(x) + 1/2 ln(y)
writing the expression as the logarithm of one quantity

2 ln(x) + 1/2 ln(y) = ln(x^2) + ln(y^1/2)

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