SOLUTION: 1. logx 8=3
2.log 10(2x-4) _ log 10(x+2) =1
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Question 360566: 1. logx 8=3
2.log 10(2x-4) _ log 10(x+2) =1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1. logx 8=3
---
x^3 = 8
x = 2
------------------
2.log 10(2x-4) - log 10(x+2) =1
---
log10[(2x-4)/(x+2)] = 1
---
[(2x-4)/(x+2)] = 10
----
2x-4 = 10x+20
8x = -24
x = -3
-----
But x cannot be -3 in the original equation
because you cannot have the log of a negative
number.
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No solution:
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Cheers,
stan H.
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