# SOLUTION: Can you please help me solve this problem? Solve for x: Log10(x-2)+log10(x+7)=1 This problem is from college algebra textbook chapter 3 This is what

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Can you please help me solve this problem? Solve for x: Log10(x-2)+log10(x+7)=1 This problem is from college algebra textbook chapter 3 This is what      Log On

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 Algebra: Logarithm Solvers Lessons Answers archive Quiz In Depth

 Question 35947: Can you please help me solve this problem? Solve for x: Log10(x-2)+log10(x+7)=1 This problem is from college algebra textbook chapter 3 This is what i have so far log10(x-2)(x-7)=1 (x-2)(x-7)=10 x2-9x+14=10 Thank youAnswer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!Can you please help me solve this problem? Solve for x: Log10(x-2)+log10(x+7)=1 This problem is from college algebra textbook chapter 3 This is what i have so far log10(x-2)(x-7)=1.......NO......(X+7) (x-2)(x+7)=10.......CORRECTED.. x2+5x-14=10 ........CORRECTED X^2+5X-14-10=0 X^2+5X-24=0 X^2+8X-3X-24=0 X(X+8)-3(X+8)=0 (X-3)(X+8)=0 X=3.SINCE X=-8 LEADS TO LOG OF NEGATIVE NUMBERS..