SOLUTION: Solve for x :log_2^x-_2 (x-1)=log_2^2 (log base 2 of x- log base 2 times x-1= log base 2 of 2)
One more please: expand:
log to the square root of x^5/ y^3
*Tonya
Algebra.Com
Question 35882: Solve for x :log_2^x-_2 (x-1)=log_2^2 (log base 2 of x- log base 2 times x-1= log base 2 of 2)
One more please: expand:
log to the square root of x^5/ y^3
*Tonya
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
Now raise everything to power 2 to remove the log-base2:
x = 2(x-1)
x = 2x - 2
2 = x
-->x=2
jon.
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