SOLUTION: Thank you for helping me out. Logarithm - EXERCISE: There are 60 wolves in a certain location. Each year there are 8.5% more wolves than in the previous year. Use the popu

Algebra.Com
Question 356444: Thank you for helping me out.

Logarithm - EXERCISE:
There are 60 wolves in a certain location. Each year there are 8.5% more wolves than in the previous year. Use the population formula for continuous growth (P=P0,e^(rt)) to determine:
a)How many wolves are in the population after 6 3/4 years?
Answer to nearest whole number.
b)How long will it take the population to double
(to the closest whole number of years)?

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
P=P[0]*e^(rt)
.
a)
60*e^(.085*6.75)
=60*e^.57375
=60*1.7749
=106 wolves are in the population after 6 3/4 years.
.
b)
60*e^.085d=120
e^.085d=2
ln(e^.085d)=ln(2)
.085d=.6931
d=8 yrs
.
Ed

RELATED QUESTIONS

You are studying wolves in the wilderness. The weights of wolves in the area are normally (answered by stanbon)
Hello, Thank you in advance for helping me out. There are two questions that have... (answered by Alan3354)
sara has $1.45 in nickles and dimes. There are 18 in all. how many of many of each are... (answered by checkley77)
Before 1918, approximately 60% of the wolves in the New Mexico and Arizona region were... (answered by stanbon)
Hello, Thanks in advance for helping me out with this math problem. I am glad there is (answered by mananth)
I was given a perfect graph for this problem however I am not sure if there: Is a... (answered by mananth)
What is the age distribution of patients who make office visits to a doctor or nurse? The (answered by richard1234)
There are approximately 500 wolves in Algonquin Provincial Park. Under ideal conditions,... (answered by CubeyThePenguin)
I really need some help solving this word problem. I have answered parts a & b but not... (answered by vleith)