SOLUTION: Please help me to solve this: 3e^-x - 4 = 9 thanks *Triston

Algebra.Com
Question 35324: Please help me to solve this: 3e^-x - 4 = 9
thanks
*Triston

Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!
3e^-x - 4 = 9 original
3e^-x = 13 add four
e^-x = (13/3) divide by 3
-x = ln (13/3) take natural log of each side
x = - ln (13/3) multiply by negative one
x is about -1.4663

RELATED QUESTIONS

please help me solve this problem... (answered by Alan3354)
Hi, could you please help me with this question: 3e^x = 5 + 8e^-x - How do you... (answered by ikleyn)
How do you solve this: 3e/5 = 6 HELP PLEASE! THANKS!... (answered by Alan3354)
Please help me solve this problem, thanks in advance. 6x+8>9, with x=4 (answered by Fombitz)
Please help me solve this equations:... (answered by checkley75)
Please help me solve this equations:... (answered by Alan3354)
please help solve this x : 2*7^(x-5)=3E^(x+2) (answered by solver91311)
solve.... (answered by ankor@dixie-net.com)
Please help me solve x^4 - 9... (answered by Grinnell,richwmiller)