SOLUTION: Please help me to solve this: 3e^-x - 4 = 9
thanks
*Triston
Algebra.Com
Question 35324: Please help me to solve this: 3e^-x - 4 = 9
thanks
*Triston
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
3e^-x - 4 = 9 original
3e^-x = 13 add four
e^-x = (13/3) divide by 3
-x = ln (13/3) take natural log of each side
x = - ln (13/3) multiply by negative one
x is about -1.4663
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