SOLUTION: In a town whose population is 2000, a disease creates an epidemic. The number of people (N) infected (t) days after the disease has begun is given by the function N(t)=2000/(1+19e^

Question 35274: In a town whose population is 2000, a disease creates an epidemic. The number of people (N) infected (t) days after the disease has begun is given by the function N(t)=2000/(1+19e^-0.6t) a. how many are initially infected with the disease (t=0)? b. how many infected after 2,5,8,12, and 16 days?
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
N(t)=2000/(1+19e^-0.6t)
N(0)=2000/(1+19(1))
N(0)=2000/(20)
N(0)=100
Initially, 100 people were infected.
--------------------------------------------
N(t)=2000/(1+19e^-0.6t)
N(2)=2000/(1+19e^(-1.2))
I do not have a calculator on me, so I will let you solve the rest of the equation. Also, all you have to do is plug in the numbers into your calculator, and you will have it all solved. I'll let you finish.
RELATED QUESTIONS
in town whose population in 3500 a disease creates an epidemic. the number of people N... (answered by josmiceli)

In a town whose population is 3500, a disease creates an epidemic. The number of people N (answered by jim_thompson5910)

The number of people who contracted a contagious disease t days after an epidemic started (answered by Cromlix)

During an epidemic , the number of people who have never had the disease and who are not... (answered by Cromlix)

The number of people infected by a disease in t days is given by N= 30,300/1+100e^.6t.... (answered by htmentor)

a) An epidemic is spreading through a large western state. Health officials estimate that (answered by ikleyn)

a) An epidemic is spreading through a large western state. Health officials estimate that (answered by Alan3354)

During an epidemic, the number of people who have never had the disease and who are not... (answered by ikleyn)