SOLUTION: Solve e^x = 3 - 2e^-x I have a problem regarding natural logs since they're a little different form the base 10 logs Thanks
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Question 350781
:
Solve
e^x = 3 - 2e^-x
I have a problem regarding natural logs since they're a little different form the base 10 logs
Thanks
Answer by
solver91311(24713)
(
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):
You can
put this solution on YOUR website!
Put everything into the LHS:
Multiply both sides by
Let
and substitute:
Factor and solve for
Verification of the last step results left as an exercise for the student.
Substitute
Take the natural log of both sides:
Use
and
Use the same process to finish determining the other root, remembering that
John
My calculator said it, I believe it, that settles it