SOLUTION: Solve
e^x = 3 - 2e^-x
I have a problem regarding natural logs since they're a little different form the base 10 logs
Thanks
Algebra.Com
Question 350781: Solve
e^x = 3 - 2e^-x
I have a problem regarding natural logs since they're a little different form the base 10 logs
Thanks
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Put everything into the LHS:
Multiply both sides by 
Let 
and substitute:
Factor and solve for 
Verification of the last step results left as an exercise for the student.
Substitute 
Take the natural log of both sides:
\ =\ \ln(2))
Use \ =\ n\,\cdot\,\log_b\left(x\right))
and \ =\ 1)
)
Use the same process to finish determining the other root, remembering that \ =\ 0)
John
My calculator said it, I believe it, that settles it
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