SOLUTION: what is the value of x in this equation: 6 log(x + 4) = log64
Algebra.Com
Question 343902: what is the value of x in this equation: 6 log(x + 4) = log64
Answer by Jk22(389) (Show Source): You can put this solution on YOUR website!
log(x+4)=log(sqrt6(64))
log(x+4)=log(2)
=>x=-2
RELATED QUESTIONS
Express the following in index form
Logx + logy =1
Logx =6
Log (x+4) = log64
Log... (answered by stanbon)
How would you solve this
Find the value of x.
log64(x) =... (answered by solver91311)
What is the value of X in this logarithm? log{{{6}}}(2x-5) + 1 = log{{{6}}}(7x+10) Please (answered by Earlsdon)
6log(x+4)... (answered by nerdybill)
How do I solve the following logarithmic equation for x?
The base of the following log (answered by stanbon)
How do I solve the following logarithm for x?
The base of the log is x.... (answered by stanbon,MathLover1)
What is the value of x in... (answered by greenestamps,josgarithmetic,stanbon,Theo)
The problem is log 4 [log 3(x)]= 1
What value of x makes... (answered by stanbon)
In the equation log(3)63 - log(3)7 = log(6)x, what is the real value of x?
I've found... (answered by Alan3354,ikleyn)