SOLUTION: 1. x=8log100(10)
Next two need to be written as a single expression with coefficient.
2. logaK-logbM-logbA
3. logb(2y+5)-1/2logb(y+3)
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Question 34286This question is from textbook college algebra
: 1. x=8log100(10)
Next two need to be written as a single expression with coefficient.
2. logaK-logbM-logbA
3. logb(2y+5)-1/2logb(y+3)
This question is from textbook college algebra
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log10 using base of 100 = (1/2)
That means 100^(1/2)=10
Your problem becomes
x=8(1/2)=4
=logaK-(logM + logbA)
=loaK-(logb(MA))
=logb(2y+3) - logb(y+3)^(1/2)
=logb[(2y+3)/sqrt(y+3)]
Cheers,
Stan H.
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